The complex conjugate of z = a + bi is z̄ = a − bi: keep the real part and change the sign of the imaginary part. For example, the conjugate of 3 + 4i is 3 − 4i. It is written with a bar (z̄) or a star (z*). A number times its conjugate is always real: (3 + 4i)(3 − 4i) = 9 + 16 = 25 = |z|2.
Reviewed by the Helping with Math Team · Updated 14 October 2026
Introduction
Each new kind of number solves equations the old kind could not. x + 5 = 2 has no answer in the natural numbers, so we need the integers (x = −3). 2x = 3 needs the rational numbers (x = 3/2). x2 = 2 needs irrational numbers (x = √2), and together these make the real numbers.
But x2 + 1 = 0 has no real answer, because no real number squared is negative. Mathematicians invented the imaginary unit i, with i2 = −1 (Euler introduced the letter i). Numbers of the form a + bi, with a and b real, are called complex numbers. Here a is the real part, Re(z), and b is the imaginary part, Im(z).
Definition
The complex conjugate of z = a + bi is the complex number with the same real part and the opposite imaginary part: z̄ = a − bi. On the complex plane, z̄ is the mirror image of z in the horizontal (real) axis.
The word “conjugate” is used the same way elsewhere in algebra: a + √b and a − √b are conjugates, and multiplying them removes the square root, just as multiplying complex conjugates removes i.
How do we write Conjugate of a Complex Number?
If z = a + bi, then its conjugate is z̄ = a − bi. Some books write z* instead of z̄. To find a conjugate, change the sign in front of i (replace i by −i).
- z = 3 + 4i → z̄ = 3 − 4i
- z = −2 − 5i → z̄ = −2 + 5i
- z = 7 (real) → z̄ = 7
- z = 6i (imaginary) → z̄ = −6i
Properties of Conjugate of Complex Numbers
Let z = a + bi, z1 and z2 be complex numbers. Then:
- Conjugate twice gives back z. The conjugate of z̄ = a − bi is a + bi = z.
- Sum: z + z̄ = (a + bi) + (a − bi) = 2a = 2 Re(z), a real number.
- Difference: z − z̄ = (a + bi) − (a − bi) = 2bi = 2i Im(z).
- Real numbers: z = z̄ exactly when b = 0, so z is real.
- Imaginary numbers: z̄ = −z (equivalently z + z̄ = 0) exactly when a = 0, so z is purely imaginary.
- Conjugate of a sum: the conjugate of z1 + z2 equals z̄1 + z̄2.
- Conjugate of a product: the conjugate of z1z2 equals z̄1 z̄2.
- Conjugate of a quotient: the conjugate of z1/z2 equals z̄1/z̄2 (z2 ≠ 0).
- Product with the conjugate: zz̄ = a2 + b2 = |z|2, which is real and never negative.
Check with z1 = 1 + 2i and z2 = 3 − i: z1z2 = 3 − i + 6i − 2i2 = 5 + 5i, whose conjugate is 5 − 5i. And z̄1z̄2 = (1 − 2i)(3 + i) = 3 + i − 6i − 2i2 = 5 − 5i. They match.
Argand Diagram of a Conjugate of a Complex Number
The complex number z = x + yi is drawn as the point P(x, y) on the complex plane, also called the Argand plane. The horizontal axis is the real axis and the vertical axis is the imaginary axis, at right angles (perpendicular).
- A real number (y = 0) lies on the real axis.
- A purely imaginary number (x = 0) lies on the imaginary axis.
- The distance from the origin to P is the modulus, |z| = √(x2 + y2), the absolute value of z.
- The angle from the positive real axis to OP is the argument, arg(z).
The conjugate z̄ = x − yi is the point (x, −y): the reflection of z in the real axis. It has the same modulus as z and the opposite argument.
z = 3 + 4i, z̄ = 3 − 4i. z + z̄ = 6. z × z̄ = 9 + 16 = 25. |z| = 5. arg z = 53.1°, arg z̄ = −53.1°.
Argument or Amplitude of a Complex number for different signs of real and imaginary parts
Let θ be the acute angle with tan θ = |y/x|. The argument of z = x + yi (taking −π < arg z ≤ π) depends on the quadrant of P:
| Signs | Quadrant | arg(z) |
|---|---|---|
| x > 0, y > 0 | First | θ |
| x < 0, y > 0 | Second | π − θ |
| x < 0, y < 0 | Third | −(π − θ) |
| x > 0, y < 0 | Fourth | −θ |
Example: z = −1 + i is in the second quadrant with tan θ = 1, so θ = π/4 and arg z = π − π/4 = 3π/4 (135°). Its conjugate −1 − i has argument −3π/4.
Multiplication of Complex Conjugate
For z1 = a + bi and z2 = c + di, multiply out like two binomials and use i2 = −1:
(a + bi)(c + di) = ac + adi + bci + bdi2 = (ac − bd) + (ad + bc)i
When the second number is the conjugate of the first (c = a, d = −b), the imaginary parts cancel:
(a + bi)(a − bi) = a2 − (bi)2 = a2 − b2i2 = a2 + b2
Example: (3 + 4i)(3 − 4i) = 9 + 16 = 25, and |3 + 4i| = √25 = 5.
Dividing complex numbers. This is the main use of the conjugate. Multiply the top and bottom by the conjugate of the bottom, which makes the bottom real:
(2 + 3i)/(1 − i) = (2 + 3i)(1 + i)/((1 − i)(1 + i)) = (2 + 2i + 3i + 3i2)/(1 + 1) = (−1 + 5i)/2 = −1/2 + (5/2)i
Key Facts and Summary
- The conjugate of z = a + bi is z̄ = a − bi (also written z*).
- z̄ is the reflection of z in the real axis: same modulus, opposite argument.
- z + z̄ = 2 Re(z) and z − z̄ = 2i Im(z).
- zz̄ = a2 + b2 = |z|2, always a real number.
- The conjugate of a sum, product or quotient is the sum, product or quotient of the conjugates.
- To divide by a complex number, multiply the top and bottom by its conjugate.
- z is real when z = z̄, and purely imaginary when z̄ = −z.
Related worksheets: complex fractions, natural numbers and subtracting whole numbers and decimals.
Complex conjugate FAQs
What is the complex conjugate of 3 + 4i?
3 − 4i. Keep the real part and change the sign of the imaginary part.
What does the bar over z mean?
z̄ means the complex conjugate of z. Some books write z* instead.
Why is a complex number times its conjugate real?
(a + bi)(a − bi) = a² − b²i² = a² + b², because i² = −1 and the middle terms cancel. For 3 + 4i the product is 25.
What is the conjugate of a real number?
The number itself. 7 = 7 + 0i, so its conjugate is 7 − 0i = 7.
How do you divide complex numbers using the conjugate?
Multiply the top and bottom by the conjugate of the bottom. The bottom becomes a real number, a² + b², and you can split the answer into real and imaginary parts.
Where is the conjugate on the complex plane?
It is the reflection of the point in the real axis: z = 2 + 3i is at (2, 3) and z̄ = 2 − 3i is at (2, −3).









